**Candle**ProblemTwo candles are the same length.

Both are lit at the same time.

The first candle (#1) burns six hours before it extinguishes itself.

The second candle (#2) burns three hours before it extinguishes itself.

During how much time must candle #1 burn before it is twice the length of candle #2?

Both are lit at the same time.

The first candle (#1) burns six hours before it extinguishes itself.

The second candle (#2) burns three hours before it extinguishes itself.

During how much time must candle #1 burn before it is twice the length of candle #2?

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two. but i can't formulate the correct equation(s). >_<

ReplyDelete2 hours

ReplyDelete1-t/6=2(1-t/3) ==> t=2

ReplyDeleteCan you explain how you cane up with that equation?

ReplyDeleteLet length of candle be 1, and the first candle burns 1/6 per hour, and the second one burns 1/3 per hour. Let t be the target length of time to be sought, so the first and second candles burn t/6 and t/3 respectively by the time the first is twice as long as the second. What remain of them satisfy the following equation:

ReplyDelete1-t/6 = 2*(1-t/3)

From the equation we get t = 2.