Search This Blog

Loading...

Hardest Math Riddle

Hardest Math Riddle - 30 January

Create a number using only the digits 4,4,3,3,2,2,1 and 1. So i can only be eight digits. You have to make sure the ones are separated by one digit, the twos are separated by two digits the threes are separated with three digits and the fours are separated by four digits

For Solution : Click Here

52 comments:

  1. Replies
    1. acuttally its both
      theyre just backwards

      Delete
    2. It's not the 12341234 one because the 4s are three didgits away from each other not four but the first one is right

      Delete
    3. Seriously? I though up my own:
      41321432

      Delete
    4. THE AMOUNT OF DIGITS BETWEEN NUMBERS DEPENDS ON THEIR NUMERICAL VALUE. You need ONE space between the 1s, TWO spaces between the 2s, etc. STICK TO THE LIMIT, YOU CANNOT USE MORE THAN THE GIVEN AMOUNT OF SPACES.
      Therefore the answer would be 41312432.

      Delete
    5. LOL mad bro?

      Delete
    6. there is only one digit between your (abid) 2s but everything else would work

      Delete
    7. The ones have to be separated by only one digit; a reason why 12341234 wouldn't work.

      Delete
    8. but anonymous, your answer is even wrong as the 1's,2's,3's and 4's are not separated by 1,2,3,4 digits respectively.

      Delete
  2. 23421314 OR 41312432 U C V MUST GIV COMPLETE ANSWER

    ReplyDelete
  3. 23421314 or 41312432

    ReplyDelete
  4. 41312432

    did not look...i'm just smart like that :)

    ReplyDelete
  5. 41312432

    how can you get it wrong!

    ReplyDelete
  6. 41312432

    its not to hard it take me 5 minutes
    to get the answer!!

    ReplyDelete
  7. Hi,
    I would like to share with you a new app that i found:
    4444 math riddle

    This app is based upon a classical problem that is most commonly formulated as follows:

    "Given no more than four instances of the digit 4,
    represent all integers using a finite number of
    mathematical symbols and operators in common use."

    In this app, you get 216 riddles (numbers) which can be expressed by four 4's and basic operation:
    Acceptable symbols and operators

    + addition
    - subtraction
    * multiplication
    / division
    sqrt4 square root of 4
    ^4 power of 4
    ! factorial, eg: n! = n * (n-1) * (n-2) * ... * 2 * 1
    . decimal point (.4 or .44)


    Create simple math arguments and try to find all the numbers.
    Example:
    The number 1 can be expressed by 4/4 (the total number of four is always up to 4)

    This app is suitable for high school / university students and for people who love mathematics and numbers riddles.
    Enjoy!

    ReplyDelete
  8. # include

    using namespace std;

    template
    bool notyet(T *arr,int size)
    { for(int i=0;i(arr,8))
    { swap(arr[rand()%8],arr[rand()%8]);
    for(int i=0;i<8;i++)
    { cout<<arr[i];
    }
    cout<<endl;
    }
    for(int i=0;i<8;i++)
    { cout<<arr[i]<<endl;
    }
    }

    ReplyDelete
  9. Replies
    1. The "3's" are only separated by two digits

      Delete
  10. Replies
    1. Erm...would like to know... HOW?!! I thought it was 41312432....

      Delete
    2. Someone that is kinda smart!! That's just wrong! You didn't get the problem at all!

      Delete
  11. Must be?? 41312432

    ReplyDelete
  12. 12341234
    wrong it says the 1's has to be 1 digit away not at least 1 digit and the 2's have to be 2 digits away not at least
    the 3's are correct
    but the 4's have to be 4 digits away not less than 4 digits

    ReplyDelete
  13. I didn't feel like doing the math, thanks people in the comment section you made my day a lot lazier ^.^

    ReplyDelete
  14. 1onedigit12twodigits23threedigits34fourdigits4

    ReplyDelete
  15. 23421314 is one answer. I wrote down each allowed combination and checked till I got above answer. Is there a more deterministic way (like solving equations) to do this ?

    ReplyDelete