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### Tricky Statement Problem

Tricky Statement Problem - 12 September

13 people came into a hotel with 12 rooms and each guest wanted his own room. The bellboy solved this problem. He asked the thirteenth guest to wait a little with the first guest in room number 1. So in the first room there were two people. The bellboy took the third guest to room number 2, the fourth to number 3, ..., and the twelfth guest to room number 11. Then he returned to room number 1 and took the thirteenth guest to room number 12, still vacant. How can everybody have his own room?

1. Nearest I can tell, the second guest doesn't have a room at the end:

Guests 3-12: Rooms 2-11
Guests 1: Room 1
Guest 13: Room 12 (was waiting in room 1)
Guest 2: Never mentioned?

1. They are supposed to have moved up, so that's why number 3 was at number 2, 4 at number 3 and so on

2. 12 guests entered the hotel with a bell boy. So as a whole 13 people entered the hotel, where as the 12 guests fit into 12 rooms at 1 room per head...

1. Doesn't that make the phrase "the thirteenth guest" fairly misleading, though?

3. No. It is impossible. Into the second room should have gone the 2nd guest, because the 13th guest was waiting in room number 1.

4. It seems he missed the second guest. The first and thirteenth are in the same room, you skipped straight to the third guest.
That means he doesnt give the 2nd guest a room....

5. there r still two guests in room no 2(guest no. 2 and 3)
so it is not possible......or else guest no 2 didn't get the room.

6. Folks...

the trick is, in the first room there were NOT two people settled in, 13. man is a guest,

in the puzzle we count him in first room with a1. man, and count him again in 12. room.

see?

7. The only way I can see around this problem is by asking "how long does each person have a room to themselves?"

The bell boy can then ask for the 2nd guest to go to room no.1, then the 1rd guest to go to room no.2, then the 3rd guest to room no.3... and so on.

To become fair, I think all the guests will have to stay for 12 days. It'll be a constant switching of rooms, where each person would get a room to themselves, but there will be two times that they have to share it. I think it would be possible to slash that down to 6 times, by making two people share a room for the first time, at the same time, but... I've been drinking a bit. :S

To do that, the bell boy would have to make two people switch room at the same time/day.

8. u missed the 2nd guest out. u said the 1st and 13th in room 1 and everyone else goes one room less than their number (e.g: guest 12 goes to room 11) so guest 2 goes to room 1 but he is not mentioned meaning everyone but him has a room

9. He had the bathroom of one person, it didn't say a bedroom merely a room.

10. Three men traveling together arrived at a hotel late one night and asked for rooms. The desk clerk told them that he only had one room left and it was a single for \$30. The men were exhausted and agreed to share the room. Each man paid \$10 and they went to the room.

Later, the desk clerk told the bellboy that he felt bad about cramming three men into one little room and he gave the bellboy \$5 with instructions to refund it to the men.

Going up in the elevator, the bellboy tried to figure out how to split \$5 evenly among three men. When he reached the room, he gave each man \$1 and he pocketed the remaining \$2.

Since each man originally paid \$10 and received a \$1 refund, they ended up paying \$9 apiece, or a total of \$27 for the room.

If you add that \$27 to the \$2 the bellboy kept, that will account for \$29 out of the original \$30. What happened to the other dollar?

11. I think the answer being "it isn't possible" makes the riddle pointless.....but if you want to answer the riddle by thinking outside of the box.......:

1. They offered the 13th guest a room at a different hotel
2. They kept him out all night and he never needed the room.
3. One or more of the "rooms" had more than one room....like a penthouse.....
4. One of the guests 1-12 is named "Everybody"