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### Easy Math Problem

Easy Math Problem - 23 January

In a strange city , there are just 2 houses.

If one person from house1 goes to house2, then the population of house2 is twice the population of house1.
While if one person from house2 goes to house1, then the population of house2 is same as the population of house1.

what the population of each house ?

For Solution : Click Here

#### 21 comments:

1. 5 in house 1 and 7 in house 2

2. 5 7
if 1 from h1 go to h2 then h2 have 8 members so 2 times of h1.
if 1 member from h2 goes to h1 than h1=h2=6

3. house 1= 5 and house2= 7 members

4. 5 in house 1 and 7 in house 2

5. h1=5 & h2=2

6. h1=5 & h2=7

7. I figured this out and I'm 10, not saying it's easy or anything. Just saying most of you say it's sooo easy when you just look and then post.
House 1 has a population of 5 and House 2 has a population of 7 as:
5 - 1 = 4 7 + 1 = 8 4 is half of 8
7 - 1 = 6 5 + 1 = 6 <- both the same
I figured this out by randomly choosing 4 and 7, knowing 4 + 1 is 8. Then, knowing

8. that I needed one more for the thing to work. So I turned the 4 to a 5 and it worked.

9. it can be both. 4 in house 1 and 5 in house 2, or, 5 in house 1 and 7 in house 2

10. house 1 is 5
house 2 is 7

11. house 2 is 6
house 1 is 7

Roald Dahl Collection

12. suganyayoganarasimhanFebruary 1, 2013 at 8:48 AM

house1 is 2 & house2 is 3

13. house1 = 5
house2 = 7

14. h1 -5
h2 -7

15. h1=3
h2=3
becasue h1-1=2 h2+1=4 then h2-1=3 h1+1=3

16. House 1 = 5
House 2 = 7