**Solve This Math Problem - 2 January**

3 kids prinka tanu and vidushi got some chocolates.

Prinka gave tanu and vidushi as many chocolates as they already had.

Then tanu gave prinka and vidushi as many chocolates as they already had.

Finally vidushi gave tanu and prinka as many chocolates as they already had.

Now each of them have 24 chocolates. How many chocolates they had originally ?

**For Solution :**Click Here

12

ReplyDelete39 12 n 21

ReplyDeleteprinka-39,tanu-21 n vidushi-12

ReplyDeleteAgree.

DeleteThis is the sequence of events. Can easily be worked out by working backwards.

P = Prinka, T = Tanu, V = Vidushi

0) P:39, T:21, V:12

P->21->T, P->12->V

1) P:6, T:42, V:24

T->6->P, T->24->V

2) P:12, T:12, V:48

V->12->P, V->24->T

3) P:24 T:24 V:24

-AO

Prinka had 39 , tanu had 21 and vidushi had 12 chocolates initially.

ReplyDeleteSolve the problem in reverse way as below :

Prinka Tanu Vidushi

24 24 24

12 12 48

6 42 24

39 21 12

prinka - 39, tanu-21, vidushi-12

ReplyDeletehouse1 is 5 pop. and house2 is 7 pop.

ReplyDeleteI think the mathematically correct answer is the below one

ReplyDeletestarting with

P T V

P-T-V 2T 2V

2(P-T-V) 2T-2P+2T+2V-2V 4V

2P-2T-2V 4T-2P 4V

3 EQUATIONS EACH IS EQUAL TO 24, Hence

^ 4V = 24 """ V=6 """

^ 4T-2P = 24

4T-24 = 2P

^ 2P-2T-2V = 24

4T-24-2T-2V = 24

2T-24-12=24

2T = 60 """ T=30 """

&

""" P=48 """