**kpit cummins Aptitude Interview Logic Question - 22 March**

Product of three consecutive numbers are 7980.

Then the sum of these consecutive numbers would be ?

**For Solution :**Click Here

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Product of three consecutive numbers are 7980.

Then the sum of these consecutive numbers would be ?

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89.33?

ReplyDelete60.....

ReplyDeleteno. are 19 20 21

60

ReplyDelete60- 19*20*21

ReplyDeleteLogic:

ReplyDelete19, 20, 21

Let's represent the 7980 as a product of prime numbers:

7980 = 19*7*3*2*2*5, as 19 is a largest prime number here, and closest number of 19 which ends with 0 or 5 is 20 => required numbers are 19, 20, 21

60

ReplyDelete60

ReplyDelete60

ReplyDelete60

ReplyDelete19*20*21=7980

ReplyDelete19+20+21=60

x(x+1)(x+2)=7980

ReplyDelete=>x3+3x2+2x-7980=0

=>(x-19)(x2+22x+420)=0

x cant -ve so x=19 other no is 20 &21

sum=19+20+21=60

Probably you are the only one who did this algebra :-D

DeleteThnxx !!

60 ; 19,20,21

ReplyDelete60 19*20*21

ReplyDeletesum: 60; 19*20*21

ReplyDelete60

ReplyDeleteNos are - 19 20 and 21

Is there any shortcut method to solve this?

take numbers as x-1, x and x+1, product is x^3-x. nearest cube to 7980 is 8000 which is 20^3 and 7980=8000-20. sum is 3x = 60

ReplyDelete