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Logical Interview Puzzle

Numbers 1-9 PuzzleLogical Interview Puzzle - 26 March

Can you divide numbers from 1 to 9 (1 2 3 4 5 6 7 8 9) into two groups so that sum of number of each group is equal.

Note : 9 cannot be turned over to make it 6.

For Solution : Click Here

17 comments:

  1. I think not...
    as there are 5 odd numbers, and 4 even...
    Any combination of the groups will leave an odd no. of odd numbers in one group...
    and the other group with even number of odds.

    So the sum can never be same....

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  2. take the sum of the nine given numbers =45
    if you want to make two groups of each equal sum of numbers...then the sum of each group should be =45/2 =22.5
    where 22.5 cant be the outcome of sum of natural numbers....

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  3. 9 cant be turned over to make it 6??? So is turning 6 to make is 9 allowed??? If so then the group is (9, 7, 1, 4, 3) and (9, 5, 2, 8) with sum of both group as 24

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    Replies
    1. I have the same doubt ..can 6 be turned over and make it 9 ????

      Delete
  4. Since nothing is mentioned, I believe we can use two-digit, three-digit numbers etc, in which case there could be several possibilities
    However, using single digits only, I feel it may not be possible...

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  5. For example
    Group 1: 75, 6, 4, 3 and 2 whose total is 90
    Group 2: 1 and 89, whose total is also 90
    I'm sure there are other possibilities

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  6. can 6 be turned over and make it 9 ????

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  7. ITS SIMPLE
    GROUP 1 9,8,1
    GROUP 2 5,6,7
    BOTH GET THE SUM 18

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    Replies
    1. your calculation is wrong unni sta. check and tell....

      Delete


  8. There are two "general solutions". In the problem, we don't see the rule that all numbers must be used from that set from 1 to 9 (lets call that S, and groups A and B). So, there are two solutions with these rules:
    1. We don't need to use all numbers from S. That means that we can create a lot of groups like, (1,2) and (3), or (1,2,8,9) and (3,4,6,7).
    2. We need to use all numbers from S. Bus, sum of numbers from 1 to 9 is 45 and 45 is not even. So, if it is not even, than, there are no two groups with sums which are equal (like, sum of A is equal to 20 if A is (1,2,8,9) and then, sum of B (3,4,5,6,7) is equal to 25 and 25 is not equal to 20).

    And, I didn't count the solution with numbers which are repeat (like (1,1,1,1) is A and (2,2) is B)

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    Replies
    1. That is my solution above - VB

      Delete
  9. This time admin has dumb ans.

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  10. 6 is inverted to make 9....Stupid answer.

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  11. Guys its so very simple...
    Group A : 1 + 2 + 4 + 6 + 8 = 21
    Group B : 3 + 5 + 7 + 6 (inverting 9 to 6) = 21
    Thats it

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  12. can make 19, 8 one group =27
    2, 3, 4, 5, 6, 7 is other group = 27

    ReplyDelete