**Logical Interview Puzzle - 26 March**

Can you divide numbers from 1 to 9 (1 2 3 4 5 6 7 8 9) into two groups so that sum of number of each group is equal.

Note : 9 cannot be turned over to make it 6.

**For Solution :**Click Here

This Blog is a collection of brain teasers, puzzles (maths,fun,brain etc), riddles,Questions, Quiz.

Can you divide numbers from 1 to 9 (1 2 3 4 5 6 7 8 9) into two groups so that sum of number of each group is equal.

Note : 9 cannot be turned over to make it 6.

Subscribe to:
Post Comments (Atom)

Difficulty Level 3/5
(710)
Logic Puzzles
(471)
Difficulty Level 4/5
(444)
Riddles
(364)
Difficulty Level 2/5
(356)
Maths Puzzles
(338)
Picture Puzzles
(320)
Trick Teasers
(278)
Popular Puzzles
(210)
Rebus Puzzles
(152)
Humor Puzzles
(149)
Series Puzzles
(123)
Interview Puzzle
(121)
What Word Am I
(96)
Difficulty Level 1/5
(90)
Trivia
(75)
Mystery Puzzles
(72)
Equation Puzzles
(68)
Difficulty level 5/5
(51)
Murder Mystery Puzzles
(43)
Square Count
(40)
Probability Puzzles
(39)
Who Am I
(39)
IAS-EXAMS
(34)
Science Puzzles
(30)
Cipher Puzzles
(28)
Situation Puzzles
(28)
Algebra
(27)
Puzzles of Age
(21)
Read Between Lines Puzzles
(18)
Google Interview Puzzle
(17)
Microsoft Interview Puzzles
(15)
Time Distance Problem
(14)
statement
(14)
Odd One Out
(13)
MatchSticks-Riddles
(12)
Relationship Puzzles
(11)
Cards
(10)
Story Puzzles
(10)
Paradox Puzzles
(8)
Classic
(6)
Directional Puzzles
(6)
Best Of 2011
(5)
clever
(5)
Brain-Twister
(4)
Mind Games
(4)
Analytical
(3)
What Does This Text Mean
(3)
CHALLENGING
(2)
Double Meaning
(2)
Acronym
(1)
Measure
(1)
Suduko
(1)
Video Riddle
(1)
coin-Puzzles
(1)
m
(1)
pop
(1)
triv
(1)

I think not...

ReplyDeleteas there are 5 odd numbers, and 4 even...

Any combination of the groups will leave an odd no. of odd numbers in one group...

and the other group with even number of odds.

So the sum can never be same....

not possible.....

ReplyDeletetake the sum of the nine given numbers =45

ReplyDeleteif you want to make two groups of each equal sum of numbers...then the sum of each group should be =45/2 =22.5

where 22.5 cant be the outcome of sum of natural numbers....

9 cant be turned over to make it 6??? So is turning 6 to make is 9 allowed??? If so then the group is (9, 7, 1, 4, 3) and (9, 5, 2, 8) with sum of both group as 24

ReplyDeleteI have the same doubt ..can 6 be turned over and make it 9 ????

DeleteSince nothing is mentioned, I believe we can use two-digit, three-digit numbers etc, in which case there could be several possibilities

ReplyDeleteHowever, using single digits only, I feel it may not be possible...

For example

ReplyDeleteGroup 1: 75, 6, 4, 3 and 2 whose total is 90

Group 2: 1 and 89, whose total is also 90

I'm sure there are other possibilities

can 6 be turned over and make it 9 ????

ReplyDeleteITS SIMPLE

ReplyDeleteGROUP 1 9,8,1

GROUP 2 5,6,7

BOTH GET THE SUM 18

your calculation is wrong unni sta. check and tell....

Deleteyou're using 1 twice...

Delete

ReplyDeleteThere are two "general solutions". In the problem, we don't see the rule that all numbers must be used from that set from 1 to 9 (lets call that S, and groups A and B). So, there are two solutions with these rules:

1. We don't need to use all numbers from S. That means that we can create a lot of groups like, (1,2) and (3), or (1,2,8,9) and (3,4,6,7).

2. We need to use all numbers from S. Bus, sum of numbers from 1 to 9 is 45 and 45 is not even. So, if it is not even, than, there are no two groups with sums which are equal (like, sum of A is equal to 20 if A is (1,2,8,9) and then, sum of B (3,4,5,6,7) is equal to 25 and 25 is not equal to 20).

And, I didn't count the solution with numbers which are repeat (like (1,1,1,1) is A and (2,2) is B)

That is my solution above - VB

DeleteThis time admin has dumb ans.

ReplyDelete6 is inverted to make 9....Stupid answer.

ReplyDeleteGuys its so very simple...

ReplyDeleteGroup A : 1 + 2 + 4 + 6 + 8 = 21

Group B : 3 + 5 + 7 + 6 (inverting 9 to 6) = 21

Thats it

can make 19, 8 one group =27

ReplyDelete2, 3, 4, 5, 6, 7 is other group = 27