**Maths Problem Puzzle - 19 September**

If we have four positive numbers a, b, c and d, there are six ways to multiply the pairs i.e. a*b, a*c, a*d, b*d and c*d. If we tell you the result of five of them without telling you which one is the product of which pair as 2, 3, 4, 5 and 6.

What is the remaining product?

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The remaining product is 10 and the numbers are 1,2,3 and 5

ReplyDeleteReason: out of the 5 given products 3 of them are prime numbers so the numbers have to be 1,2,3 and 5 (a=1, b=5, c=3 and d=2)...

so axb = 5, axc=3, axd=2, bxd=6, cxd=10 and the remaining product dxd = 4 is mentioned in the question...

I dont think there is a solution. As stated above, 3 of the given products (2,3,5) are prime, so there must include 1,2,3 and 5. But that would give products of 2, 3, 5, 6, 10 and 15.

ReplyDelete