**Interesting Math Question - 16 October**

Bobby and Wilbur decided to take their respective car out of the garage and race. None of them cheated and they both stood at the start time and decided to cover a distance in full throttle. The first to reach the mark was to be declared the winner.

Upon reaching the finishing mark, they found out that Bobby's car is 1.2 times faster than Wilbur's. Now, Wilbur had reached the mark about 1 minute and 30 seconds later than Bobby. Bobby's car reached the mark at 60 MPH on average.

Can you calculate the distance between the starting mark and the final mark with the help of the given data?

**For Solution :**Click Here

Consider Wilbur Speed as 'x' and his time taken as 't';

ReplyDeleteSo Bobby's Speed is 1.2x. and his time taken 't+90'

They cover the same distance, so

=> x.t = (1.2x).(t+90)

Solving, we get,

t = 450 seconds.

----------------------

So, Distance = x.t for Bobby or (1.2x)(t+90)

For bobby:

Distance = 60 MPH * 450 seconds

= 60/3600 Miles per second * 450

= 7.5 Miles

Answer : 7.5 Miles

7.5miles is ok

Deletebut the initial equation is x.t = (1.2x)(t-90)

as speed increases from x to 1.2x, time taken will be less

Typo :D

Deletet = 0.125 h

ReplyDeletew = 60 mph

L = 7.5 miles