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Hard Aptitude Number Series

Hard Aptitude Number Series - 26 December

Can you solve this hard number series problem ?

7, 8, 10, 12, 16, 18 ?

For Solution : Click Here

4 comments:

  1. One acceptable solution (there may be others also) is:
    7, 8, 10, 12, 16, 18, 22, 24, 28, 34,...
    a(n)=n-th prime+ 5
    (2+5=7, 3+5=8, 5+5=10, 7+5=12,... )

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  2. 2^3 - 1, 2^3, 2^3+2, 2^4-4 , 2^4 , 2^4+2, 2^5 - 7 , 2^5 , 2^5+2....

    Here I m substracting the position of a number.

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  3. 22

    Its is series of prime numbers + 5

    1st 7 Prime nos are :
    2 , 3 , 5 , 7 , 11 , 13 , 17
    Adding 5 =>
    7 , 8 , 10 , 12 , 16 , 18 , 22(Ans)

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