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Interesting Maths Question

Interesting Maths Question - 11 December

I am working in a bus company. The company recently went under expansion and therefore there was not enough room for all the buses. As a result, twelve buses had to be stored outside.

If the company decides to expand the garage space by forty percent, enough space to accommodate the current buses will be created leaving enough space for twelve more buses if the need arises in future.

Can you calculate the number of buses that the company owns at present?

For Solution : Click Here

12 comments:

  1. The current capicity of the parking lot is 60 buses and 12 are parked outside thus the company has 72 buses. After increasing the garrage space by 40% it will be able to accomadate 24 additional buses (72 in the current fleet and additional 12 empty slots) the new garrage will have a total of 84 slots.

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  2. 84 is the answer ....ez question

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  3. At present company owns 72 buses

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  4. 40% of x = 24, x= 60, new = 60+24 = 84

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  5. those who put 72 as ans ,explain

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  6. 60 is answer..suppose it has 100 bus now. increasing it by 40% is 140..so for 1 bus it wil be 100/40=2.5 then for 24 buses it will be 2.5 *24= 60 bus

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  7. 72

    The company owns seventy two buses at present.

    Let us assume that they have B buses right now and S space before the expansion. Now the space is enough for
    S = B - 12 ----- [1]

    When they expand, they will have more space which will be enough for
    S + 0.4 x S = B + 12 ------ [2]
    => 1.45 = B + 12
    Also, B = 1.45 - 12 ----- [3]

    Now we can rewrite the equation [1] as
    B = S + 12 ----- [4]

    Equating the third and fourth equation, we get
    1.4 S - 12 = S + 12

    Subtract S from both sides
    0.4 S - 12 = 12

    Now add 12 to both sides
    0.4 S = 24

    Multiply by ten and divide by four on both sides
    S = 60

    Put the value in fourth equation
    B = 72

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  8. misinterpretation b/w bus & space,thnks admin

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  9. X-number of buses
    Y-area of each bus
    Z-present area of garage

    1.4(X-12)Y=(X+12)Y
    X=72

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