**Who Survives Hard Logic Puzzle - 3 December**

Suppose there are 100 people standing in a circle. The first person has a gun in hand. What he has to do is shoot the second person and then pass the gun to the third person. Now, the third person kills the fourth person and gives gun to the fifth person.

This process is carried till there is only one person surviving. Can you find out who survives at the end ?

**For Solution :**Click Here

First one will always survive

ReplyDelete#73 will win

ReplyDelete"Josephus problem" (google it! )

ReplyDelete2^m +k=n --->2^6 +36=100 (2^6 is the largest power of 2 smaller or equal to 100)

winner =2k+1 =2*36+1=number 73

73 Will be the winner.

ReplyDelete73 will not be shot!

ReplyDelete- I have started a new brain teaser blog and it would be great if you could check it out (:

http://dailybrainbuster.blogspot.com/?m=1

63, help me out , tell the way how u solve it

ReplyDeleteplease save me, tell me the approach

ReplyDeleteCheck this article out. It is very explanatory.

ReplyDeletehttp://www.exploringbinary.com/powers-of-two-in-the-josephus-problem/

My son knew if he started it he would be the last standing, based on probability.

ReplyDelete(I simply don't understand how his mind works things out so fast)