By using all numbers, i.e. 123456789 and subtraction/addition, operators number 100 can be formed in many ways.

Example 98 + 7 + 6 - 5 - 4 - 3 + 2 - 1 = 100

But if we add a condition that use of the number 32 is the must. Then there are limited solutions.

One of such solution is: 9 - 8 + 76 + 54 - 32 + 1 = 100

Can you tell any other solution?

Labels: Difficulty Level 4/5, Maths Puzzles, Series Puzzles