tag:blogger.com,1999:blog-2893315201359920156.post8519224316422051909..comments2023-10-28T20:35:12.856+05:30Comments on Best Brain Teasers: Challenging Logic Puzzlelaveshhttp://www.blogger.com/profile/03731980294342074301noreply@blogger.comBlogger24125tag:blogger.com,1999:blog-2893315201359920156.post-45711122998093721892016-02-19T10:04:17.904+05:302016-02-19T10:04:17.904+05:30Minimum is 1 if you are lucky
but 2 for a safe an...Minimum is 1 if you are lucky <br />but 2 for a safe answer every timeAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-38341716292470067212013-06-16T19:21:49.428+05:302013-06-16T19:21:49.428+05:30divide into 3 sets of coins...and balancing any 2 ...divide into 3 sets of coins...and balancing any 2 sets of coin...if it s equal then the 3rd set will contain the fake one...in 1st step we evaluate any one of 3 sets contain the fake one.....nxt step will be divide the 3 coins into 1,1,1....balance any 2 coins and rest the remainin one....if the balance s equal then the rest one will be the fake one.....Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-68271271296346649752013-06-16T19:15:38.531+05:302013-06-16T19:15:38.531+05:3022Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-67108618783955512082013-06-14T10:15:55.374+05:302013-06-14T10:15:55.374+05:30The answer is zero weightings. If one coin is inde...The answer is zero weightings. If one coin is indeed fake, it would be of a different make then, yes? And if it is of a different make, then it would produce a different sound when dropped, right? So I'd say, just drop each coin on a hard surface till you hear the one that sounds different.Anonymoushttps://www.blogger.com/profile/08358521529723261119noreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-4215768249494593242013-05-21T04:28:45.785+05:302013-05-21T04:28:45.785+05:30Actually because of the shit wording of the puzzle...Actually because of the shit wording of the puzzle the answer is 1. Least number of weightings to find the couterfeit coin is 1 - you might get lucky and just weigh it next to one of the fine ones. If the question said to be CERTAIN of finding the counterfeit then the answer is two:<br /><br />split nine into 3 groups of three (1) (2) and (3)<br /><br />weigh (1) against (2)<br /><br />2 possibilities:<br /><br />possibility 1: (1)=(2)<br />therefore counterfeit is in group (3)<br />If any two coins from group (3) are weighed against each other there are another 2 possible outcomes:<br />(3(1))=(3(2)) therefore (3(3)) is counterfeit<br />(3(1))!=(3(2)) therefore whichever is lighter is the counterfeit<br /><br />possibility 2: (1)!=(2)<br />therfore the lighter group contains counterfeit<br />follow same step as 1st possibility for the group containing the lighter coin to find the counterfeitAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-90505256617301852092012-12-11T01:54:01.483+05:302012-12-11T01:54:01.483+05:30The answer is 1 weighting. If you happen to get th...The answer is 1 weighting. If you happen to get the fake and weigh it against 1 real, you will see it's lighter. 1 weighting.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-81628163252886150422012-11-15T06:42:19.124+05:302012-11-15T06:42:19.124+05:30This comment has been removed by the author.Anonymoushttps://www.blogger.com/profile/12270896598741219560noreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-3031078265909713832012-10-17T00:21:25.588+05:302012-10-17T00:21:25.588+05:30
2
ilovegrace.1210<br /><br />2<br /><br /><br />ilovegrace.1210Anonymoushttps://www.blogger.com/profile/09693085594532435792noreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-67572862423865499922012-09-19T01:15:38.118+05:302012-09-19T01:15:38.118+05:30its 3 only, We cant distribute into of 3 pair each...its 3 only, We cant distribute into of 3 pair each because balancing exist only in 2 sideRAJESH CHAND UPPADHAYhttps://www.blogger.com/profile/02590659495695649339noreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-16434290324146082392012-09-15T21:40:32.826+05:302012-09-15T21:40:32.826+05:30no way 2 times.no way 2 times.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-57937105283418342672012-06-16T08:52:27.036+05:302012-06-16T08:52:27.036+05:303.
First we take 4 coins on each pan of the balanc...3.<br />First we take 4 coins on each pan of the balance leaving one outside. If both the pans are balanced, the left one is fake. If one pan is lighter than the other, the fake coin is among those four in it.So we weigh them dividing into two halves, i.e., 2 coins on each pan. One pan will be lighter, containing the fake coin. Then we weigh the third time: one coin on each pan. The lighter will be visible clearly.Anonymoushttps://www.blogger.com/profile/13017221221858202848noreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-78865706161005237012012-03-12T12:04:14.736+05:302012-03-12T12:04:14.736+05:30first take the coins in the multiple of 3 as soon ...first take the coins in the multiple of 3 as soon as possible in this qn. 3 3 3 check first 3 3 if the coins are not equal divide another 3 coins into 1 1 1 check first 1 1 if the coins are not equal weight then the last one coin is the weightless one <br />common formula is 3^n where n is nearly power of 3.sathiknoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-24529219112209594002011-08-26T12:54:32.737+05:302011-08-26T12:54:32.737+05:30in only 3 weighings by the way!in only 3 weighings by the way!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-63935097981536125322011-08-26T12:53:51.272+05:302011-08-26T12:53:51.272+05:30Minimum 2. Smaller-easier version of 12 coins, one...Minimum 2. Smaller-easier version of 12 coins, one is lighter/heavier, how do you find odd one out? (dont;'t know if it is lighter/heavier)Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-30753897983009873572011-08-25T19:36:42.993+05:302011-08-25T19:36:42.993+05:30minimum 2 weight
maximum 6 weightminimum 2 weight<br />maximum 6 weightDaily Puzzleshttp://adailypuzzles4u.blogspot.comnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-86107197866973477832011-08-25T16:10:06.123+05:302011-08-25T16:10:06.123+05:3022Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-50255187661103120962011-08-25T15:22:04.196+05:302011-08-25T15:22:04.196+05:30Minimum 2 weightMinimum 2 weightRizwanhttps://www.blogger.com/profile/08950068596662062604noreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-8276228099327289632011-08-25T14:23:37.108+05:302011-08-25T14:23:37.108+05:30The Answers is - 2.
Divide coin to 3 group-A,B,C. ...The Answers is - 2.<br />Divide coin to 3 group-A,B,C. each 3 coin.<br /><br />In First weight, A & B to find the lightest of A,B,C.<br /><br />if weight of A is more than B. than B is lightest and vice-cersa.<br />if both are same weight than C is Lightest.<br /><br />In Second weight, find the fault coin in lightest group. by wighting two coin same like above.jaykissanhttps://www.blogger.com/profile/16425512490607278066noreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-74292240140110630672011-08-25T13:49:42.612+05:302011-08-25T13:49:42.612+05:30Ya 2 is the minimumYa 2 is the minimummyideashttps://www.blogger.com/profile/03968298371672457885noreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-29693012090559664772011-08-25T13:08:57.994+05:302011-08-25T13:08:57.994+05:30divide 3+3+3
weight 3-3 if equal odd one is in rem...divide 3+3+3<br />weight 3-3 if equal odd one is in remaining 3<br />weight 1-1 if equal odd one is rem<br />So, Total 2 weightsRahul's pagehttps://www.blogger.com/profile/17761442328241254927noreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-37932207033715213272011-08-25T13:07:12.586+05:302011-08-25T13:07:12.586+05:30why 2why 2Sameernoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-3204337501283325582011-08-25T13:01:36.272+05:302011-08-25T13:01:36.272+05:302. I think....2. I think....Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-75991606677574349352011-08-25T12:48:55.424+05:302011-08-25T12:48:55.424+05:3022Nandhttps://www.blogger.com/profile/01663793504796156194noreply@blogger.comtag:blogger.com,1999:blog-2893315201359920156.post-2564284268485144662011-08-25T12:38:39.218+05:302011-08-25T12:38:39.218+05:3033sameernoreply@blogger.com