**Algebra Maths Equation Riddle - 24 May**

Can you solve the below algebraic mathematical equation?

(J+O+I+N+T)3 = JOINT

**For Solution :**Click Here

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Can you solve the below algebraic mathematical equation?

(J+O+I+N+T)3 = JOINT

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(J+O+I+N+T)3=(J+O+I+N+T)cube

ReplyDelete17576

ReplyDelete(1+7+5+7+6)^3=17576

well my answer to that was more logical than other things.

ReplyDelete(j+o+i+n+t)3= JOINT

lets say : j+o+i+n+t = Y

Means that if we add those numbers potency 3 = 5 digits

Using calculator you realise that the number 22 is the first potency 3 has 5 digits.

22*22*22=10648

the last number is 46

46*46*46= 97336

so we know that the total of the numbers is between 22 and 46.

we will check the minimum / maximum sum of five numbers ( j+o+i+n+t)

if we do 1+2+3+4+5 = 15 ( not possible as between 22 and 46)

2+3+4+5+6= 20 not possible as between 22 and 46.

3+4+5+6+7= 25 possible, now we know its between 25 and 46

The maximum will be : 9+8+7+6+5= 35 this max so the sum is between 25 and 35.

Using calculator you just have to do 25*25*25= 15'625 not good one as number five is shown twice

26*26*26= 15 756 not good one as number five as well is shown more than one time

27*27*27= 19 683 this could be used as total of 1+9+6+8+3= 27

28*28*28= 21 952 not good one as number two is shown twice

29*29*29= 24 389 this could be used however their sum isnt 29

32*32*32= 32 768 this could be used however their sum isnt 32

Hop dat helpd lil bit, as said its more logical than mathematical.